how to start a python file from python code

wxPython Users
1

Hello,

I have trying to launch another application from Python using spawn unedr WinXP but no success. I had to use startfile.
But startfile is not recognized by Linux… any idea ?

here is my code:
mpath = os.getcwdu()
marg = mpath+"\plugins\mplplotter.py" #+’ --’+str(self._iddp)
os.startfile(marg)
but does work on winXP but not linux…
I know it is not wxpython… but well there is smart people in this list…

Thanx

Robert

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2

Use either the subprocess module or os.system()

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On 2007-04-03, Robert VERGNES <robert.vergnes@yahoo.fr> wrote:

I have trying to launch another application from Python using spawn unedr WinXP but no success. I had to use startfile.
But startfile is not recognized by Linux... any idea ?

--
Grant Edwards grante Yow! Everybody is going
                                  at somewhere!! It's probably
                               visi.com a garage sale or a disaster
                                                   Movie!!

3

Is the first line of mplplotter.py something like:

#!/usr/bin/env python

If not, then base linux usually won't understand know how to handle it.

- Josiah

···

Robert VERGNES <robert.vergnes@yahoo.fr> wrote:

Hello,

I have trying to launch another application from Python using spawn unedr WinXP but no success. I had to use startfile.
But startfile is not recognized by Linux... any idea ?

here is my code:
mpath = os.getcwdu()
marg = mpath+"\\plugins\\mplplotter.py" #+' --'+str(self._iddp)
os.startfile(marg)
but does work on winXP but not linux...
I know it is not wxpython... but well there is smart people in this list...