From what I understood, his error was that BusyCursor wasn't in effect
when he ran EndBusyCursor, so I don't think your solution will get rid
of his error. I could be wrong though!
--vicki
···
-----Original Message-----
From: Uwe C. Schroeder [mailto:uwe@oss4u.com]
Sent: Wednesday, July 28, 2004 3:11 PM
To: wxPython-users@lists.wxwidgets.org
Subject: Re: [wxPython-users] wxBusyCursor()-----BEGIN PGP SIGNED MESSAGE-----
Hash: SHA1Or you can just check if the window is busy by doing:
if wx.IsBusy():
wx.EndBusyCursor()Thus avoiding the error if some other routine already ended
the busy statusOn Wednesday 28 July 2004 11:31 am, Stanfield, Vicki >{D167~Indianapolis} >wrote:
Well, you have to make sure you call the wxEndBusyCursor
only when the
wxBeginBusyCursor is running. Think of it like a wrapper. Start the
busy cursor, do something that you want to see the busy cursor for,
and then end the busy cursor. Here is an example as taken from the
demo:if os.path.exists(itemText + '.py'):
wx.BeginBusyCursor()
wx.LogMessage("Running demo %s.py..." % itemText)
try:
self.LoadDemoSource(itemText + '.py')if (sys.modules.has_key(itemText)):
reload(sys.modules[itemText])module = __import__(itemText, globals())
self.SetOverview(itemText + " Overview",
module.overview)
finally:
wx.EndBusyCursor()
self.tree.Refresh()--vicki
-----Original Message-----
From: Heimburger, Ralph P [mailto:rpheimburger@babcock.com]
Sent: Wednesday, July 28, 2004 1:04 PM
To: wxPython-users@lists.wxwidgets.org
Subject: RE: [wxPython-users] wxBusyCursor()Yes, your solution seems to work visually but now I get
an error in
the console:
line 28, in workingStatus
wx.EndBusyCursor()
line 250, in EndBusyCursor
return _misc.EndBusyCursor(*args, **kwargs)
wx.core.PyAssertionError: C++ assertion
"wxAssertFailure" failed in
..\..\src\ms
w\utilsgui.cpp(176): no matching wxBeginBusyCursor() for
wxEndBusyCursor()Ralph Heimburger * Enterprise Systems
The Babcock & Wilcox Company*20 S. Van Buren Ave.*Barberton, OH
44203*(330) 860-1858-----Original Message-----
From: Stanfield, Vicki {D167~Indianapolis}
[mailto:vicki.stanfield@ROCHE.COM]
Sent: Wednesday, July 28, 2004 1:48 PM
To: wxPython-users@lists.wxwidgets.org
Subject: RE: [wxPython-users] wxBusyCursor()I think it should look more like this:
def workingStatus(self, mode):
self.statusBar.text=mode
if mode==;Working':
wx.BeginBusyCursor()
else:
wx.EndBusyCursor()
But that being said, I've only used this in the demo
code. If this
function doesn't get called at the end of the time you want the Busy
Cursor, you'll want to move the EndBusyCursor call.--vicki
-----Original Message-----
From: Heimburger, Ralph P
[mailto:rpheimburger@babcock.com]
Sent: Tuesday, July 27, 2004 12:24 PM
To: wxPython-users@lists.wxwidgets.org
Subject: [wxPython-users] wxBusyCursor()I wrote a function that I call with "modes". When the
mode is 'Working' I want the cursor to be an hourglass.The function is defined as follows:
def workingStatus (self, mode):
self.statusBar.text=mode
if mode=='Working':
dowait=wx.wxBusyCursor()
else:
dowait=None
When I call the function with this command:
self.workingStatus('Working')It updates the StatusText, but does not change the
cursor. Why?Ralph Heimburger * Enterprise Systems
The Babcock & Wilcox Company*20 S. Van Buren
Ave.*Barberton, OH
44203*(330) 860-1858
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Phone: +1 650 872 2425 San Bruno, CA 94066
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Fax: +1 650 872 2417
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