scott2
1
I was wondering if there is a better way to write this codelet.
I have read that 'range(len(aList))' is poor form. ('Dive into Python', pg 107)
>>> li = [[1,1,'w'],[2,2,'e'],[3,3,'dddd']]
>>> q = [li[v][2] for v in range(len(li))]
>>> q
['w', 'e', 'dddd']
li could be a list of 1 item or 5,000 items, so I am looking for a faster way if one exists. q is what I am after.
Thanks
Scott
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In your example I would write;
li = [[1,1,'w'],[2,2,'e'],[3,3,'dddd']]
q = [x[2] for x in li]
···
-----Original Message-----
From: scott [mailto:scott@ebbyfish.com]
Sent: 05 April 2005 22:42
To: wxpython-users@lists.wxwidgets.org
Subject: [wxPython-users] simple question
I was wondering if there is a better way to write this codelet.
I have read that 'range(len(aList))' is poor form. ('Dive into Python',
pg 107)
>>> li = [[1,1,'w'],[2,2,'e'],[3,3,'dddd']]
>>> q = [li[v][2] for v in range(len(li))]
>>> q
['w', 'e', 'dddd']
li could be a list of 1 item or 5,000 items, so I am looking for a
faster way if one exists. q is what I am after.
Thanks
Scott
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No virus found in this outgoing message.
Checked by AVG Anti-Virus.
Version: 7.0.308 / Virus Database: 266.9.3 - Release Date: 4/5/2005
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Ah, the obvious! Thank you so much!
Scott
Nikolai Kirsebom wrote:
···
In your example I would write;
li = [[1,1,'w'],[2,2,'e'],[3,3,'dddd']]
q = [x[2] for x in li]
-----Original Message-----
From: scott [mailto:scott@ebbyfish.com] Sent: 05 April 2005 22:42
To: wxpython-users@lists.wxwidgets.org
Subject: [wxPython-users] simple question
I was wondering if there is a better way to write this codelet.
I have read that 'range(len(aList))' is poor form. ('Dive into Python', pg 107)
>>> li = [[1,1,'w'],[2,2,'e'],[3,3,'dddd']]
>>> q = [li[v][2] for v in range(len(li))]
>>> q
['w', 'e', 'dddd']
li could be a list of 1 item or 5,000 items, so I am looking for a faster way if one exists. q is what I am after.
Thanks
Scott
--
No virus found in this outgoing message.
Checked by AVG Anti-Virus.
Version: 7.0.308 / Virus Database: 266.9.3 - Release Date: 4/5/2005