I have a class that accepts *args and **kwargs as it's initialization
parameters and I want to be able to set a class "property" for each of
the keywords, is there a way to do this?
#### Sudo-code Start ####
class Sample:
def __init__(self, *args, **kwargs):
for property in kwargs.keys():
self.{property} = kwargs[property]
data = Sample(test='test1', more='more testing', int=7)
print data.test
#### Sudo-code End ####
You cannot define properties within the __init__ method, those need to
be defined when defining your class. But that's ok, I don't think you
meant what you said.
However, if you just want to set attributes, there are at least a couple
different ways:
class Sample:
def __init__(self, *args, **kwargs):
self.__dict__.update(kwargs)
class Sample:
def __init__(self, *args, **kwargs):
for i,j in kwargs.iteritems():
setattr(self, i, j)
The latter should work in all cases, but the former won't work in the
following case...
class Sample(object):
__slots__ = ['test', 'more', 'int']
def __init__(self, ...):
...
other = property(...)
In the above example with __slots__ and properties, only the second
example using setattr will work, as the object has no __dict__.
- Josiah
"Dj Gilcrease" <digitalxero@gmail.com> wrote:
I have a class that accepts *args and **kwargs as it's initialization
parameters and I want to be able to set a class "property" for each of
the keywords, is there a way to do this?#### Pseudo-code Start ####
class Sample:
def __init__(self, *args, **kwargs):
for property in kwargs.keys():
self.{property} = kwargs[property]data = Sample(test='test1', more='more testing', int=7)
print data.test
#### Pseudo-code End ####